Home » Ask & Discuss » Mathematics. » Algebra « Back to Discussion

Algebra

Blazing goIITian

Joined:	27 Aug 2009
Post:	637

18 Mar 2010 15:16:44 IST

0 People liked this

341

circular permutation

None

If n distinct objects are arranged in a circle then the number of ways of selecting 3 of these things so that no 2 of them are next to each other is A. ( n(n-4)(n-6) )/12 b. ( n(n-4)(n-5) )/6 C. ( n(n-3)(n-4) )/6 D. ( n(n-4)(n-6) )/4

Share this article on:

Comments (2)

never say never

Hot goIITian

Joined: 19 Nov 2009

Posts: 153

19 Mar 2010 05:20:56 IST

Like 0 people liked this

kya ans option 3 hai mera pura nahi ayya but ifyou can select the first things in n way the you can select thenext thing in (n-3) ways but

vijay kharya

Blazing goIITian

Joined: 27 Aug 2009

Posts: 637

19 Mar 2010 11:32:26 IST

Like 0 people liked this

sorry friend but your answer is wrong. please can someone explain the answer. it is given as option b

Quick Reply

Reply

	Some HTML allowed.
	Keep your comments above the belt or risk having them deleted.
	Signup for a avatar to have your pictures show up by your comment
	If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team