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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 May 2008 11:44:04 IST
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d 8th term in d expansion of 1/ 9th rt (1-2x) wer IxI <1/2 is
d 5th term in d expansion of 1/nth rt ( -nx ) is
d coefficient of x 4 in d expansion of (1-2x+3x2 -4x3 +..............) -n is
d coefficient of x 4 in d expansion of (1+2x+3x2)10 is
d value of [ 31/2 --{4+51/2 +(17--4(5)1/2 } ]1/2 is ?
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1 May 2008 12:12:03 IST
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(1+2x+3x^2)^10 =(1+2x+3x^2)(1+2x+3x^2)(1+2x+3x^2).....10times
now x^4 can be obtained by multiplying
x^2.x^2 which gives 9 and this can be done in 10c2 ways
x^2.x.x which gives 12 and this can be done in 10.10c2 ways
x.x.x.x which gives 16 and this can be done in 10c4 ways
so the ans is 9.10c2+120.10c2+16.10c4
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1 May 2008 13:12:36 IST
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can u giv d ans for d oder quesns
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2 May 2008 21:16:16 IST
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comn u can do it plz do d 2nd 1 also
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6 May 2008 18:19:01 IST
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ive tried 4 d last sum its easy & ive got it as 1
can i giv d soln 4 it
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7 May 2008 18:04:55 IST
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comn giv d reply plz
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9 May 2008 22:58:47 IST
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hey i no d ans frnd can i giv d soln 4 it hey wer r u frnds chalo jaldi batao
are are areeee im sry yaaron vait ill type d last quesn correctly
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9 May 2008 23:02:20 IST
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dekho yeh actually
{ rt3 -- [4+rt5 +rt( 17--4rt5 ) ]1/2 }1/2 dis is d quesn imsry again
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12 May 2008 12:17:25 IST
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hey plz reply can i giv d soln
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14 May 2008 10:40:47 IST
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aap log kyun kuch nahin bolte
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15 May 2008 18:50:10 IST
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plz tell me about oder quesn
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15 May 2008 19:47:22 IST
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}^{\frac{p}{q}} = 1-p(\frac{x}{q})%2B\frac{p(p-q)}{2!}({\frac{x}{q}})^{2}-\frac{p(p-q)(p-2q)}{3!}({\frac{x}{q}})^{3}%2B\\\ldots%2B\frac{p(p-q)(p-2q)\ldots[p-(r-1)q]}{r!}({\frac{-x}{q}})^{r}%2B\ldots\infty)
}^{-2}=1-2x%2B3{x}^{2}-4{x}^{3}\ldots\infty\;so\\{1-2x%2B3{x}^{2}-4{x}^{3}\ldots\infty})^{-n}={(1%2Bx)}^{2n}\\now\;u\;can\;do\;this\;q\;too\;i\;am\;really\;sorry\;bcos\;i\;could\\have\;posted\;this\;before\;but\;i\;felt\;lazy\;to\;refer\;to\;the\\formula\;i\;dint\;remember\;the\;formula\;i\;am\;sorry\;once\\again\;u\;were\;really\;patient\;i\;should\;say\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;.)
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