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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: common term
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umang (229)

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Find the largest term common in sequences 1,11,21,31,41,..... to 100 terms   and 31,36,41,46,51,56,.... to 100 terms  ????????

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saarika (270)

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is the answer 521???
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umang (229)

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Hey !
actually , it aws an objective question . and the answer given is 471 . Pls explain how u got ur answer !!!!!

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saarika (270)

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in the first series 1,11.... the 100th term is 991 (by the formula Tn=a+(n-1)d)
 
in the second series31,36,41............100th term is 526.
 
first series is 1,11..........521.......991
 
second series is 31,36..........516,521,526
 
hence the largest common term is 521.
 
is there any mistake in my solution?? please let me know..
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saarika (270)

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reply soon!!!!!!
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unavailable (9)

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common differences of first series= 10
common differences of second series= 5
first common term = 41
 
if you observe closely
 
there will be a sequence for common terms with common difference 10*5=50
 
hence the sequence will be
 
41, 91, 141, 191 .....................
 
as saarika found it last terms of the two sequences are 991,and 526.
 
take the minimum one
 
i.e 526
 
41+(n-1)50=526
n=10.7
 
n is a integer so n=10
 
putting in the formula
 
t 10  = 491
 
i think 471 is not the answer as it does not satisfy the equation
 
if 491 in the option!!!!
 
please verify   
 

Shashank nayak
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Post 03/03/2007 22:52     Subject: Re:common term

common differences of first series= 10
common differences of second series= 5
first common term = 31
 
if you observe closely
 
there will be a sequence for common terms with common difference 10
 
hence the sequence will be
 
31,41,51.....................
 
as saarika found it last terms of the two sequences are 991,and 526.
 
take the minimum one
 
i.e 526
 
31+(n-1)10=526
n=50.5
 
n is a integer so n=50
 
putting in the formula
 
t 10  = 521
sorrrrrrrrrrrrry!!!!!!!!!
 
521 is right
saarika is right
 
ignore the first post
 

Shashank nayak
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magiclko (4210)

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521 will be the answer,
see it can be solved logically also, the first series's numbers ranging frm [1,526) all will be also of that of the other series, so defintely 521 will be the answer,
hey umang,hav u taken this question frm fiitjee package??? its given thr also as 471... but the answer is defintely 521!!!

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rajat (284)

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hey ,the answer is 521.bcoz 521 occurs in both the  series which is of course >471
i do not care what the book says bcoz if u can see it with ur eyes that it is 521,why should we say that we are wrong and the book is right ????

light travels the fastest ??? NO
wherever light goes it always finds that darkness has already got there
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umang (229)

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Hey shashank !!
yes , ur solution is correct .
And sarika ,you hav applied hit and trial method , though ur answer is correct. I dont know why the book says the answer=471 , but yes , 521 must be the correct answer !!!!!!! 
 

Umang
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