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Community Discussion Question:
complex again :(
Forum Index
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Algebra
Author
Message
23 Nov 2007 16:16:01 IST
Subject:
complex again :(
twinkle_star
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if # = z / z - (1/3 i)
and | # | = 1
then
z lies on????????
a) circle
b) ellipse
c) hyperbola
d)none of these
23 Nov 2007 16:19:33 IST
Subject:
Re:complex again :(
Accepted Answer
[?]
nadeemoidu
(
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| z / (z - i/3 ) | =1
| z | = | z- i/3 |
|z| is the distance of z from the origin.
|z-i/3 | is the distance of z from the point ( 0 , 1/3) .
distance of z from 2 points are equal . the locus is a straight line
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23 Nov 2007 17:08:49 IST
Subject:
Re:complex again :(
ritu_007
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hiiiii
given I#I=1
#= z/z-(1/3i)
put z= x+iy
IzI/Iz-(1/3i)I=1
Ix+iyI/Ix+i(y-1/3)I=1
x
2
+y
2 =
x
2
+(y-1/3)
2
x
2
+y
2
=x
2
+y
2
+1/9-2/3y
so it passes through y=0,which is a straight line.
so ans=(d).
"OUR GREATEST GLORY IS NOT IN NEVER FALLING.BUT IN RAISING EVERTIME WE FALL".
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