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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: complex algebra
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gcch29 (416)

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Olaaa!! Perrrfect answer. 68  [106 rates]

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1) Let C denote the set of complex nos. and R the set of real nos. Let the function f :C---->R be defined by f(z)=|z| then
a)f is injective but not surjective
b)f is surjective but not injective
c)f is neither surjective  nor  injective
d)f is both surjective and injective
 
2)The roots of eqn zn =(z+1)n on the complex plane lie on the line
a)2x+1=0
b)2x-1=0
c)x+1=0
d)x-1=0
 
3)If cos(1-i) = a+ib where a,b are real nos. i = (-1)^1/2
a) a=[(e-1/e)cos1]/2 ,b=[(e+1/e)sin1]/2
b) a=[(e+1/e)cos1]/2 ,b=[(e-1/e)sin1]/2 
c) a=[(e+1/e)cos1]/2 ,b=[(e+1/e)sin1]/2
d) a=[(e-1/e)cos1]/2 ,b=[(e-1/e)sin1]/2

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gcch29 (416)

Hot goIITian

Olaaa!! Perrrfect answer. 68  [106 rates]

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total posts: 164    
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anyone plz reply
he will be rated for his efforts

Your attitude determines your altitude
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