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Ask iit jee aieee pet cbse icse state board experts Expert Question: Complex no.
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sarvpriye (36)

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1.)
Let z1 &z2 be any two arbitrary complex nos, then prove that :
| z1 + z2| >= 1/2(|z1| +|z2|) | z1/|z1| + z2/|z2| |
 
2.)
If sin log (ii) = a +ib. find a and b. Hence find  cos(log ii).
 
Ans. a= -1, b= 0,   0
 
    
KAB (1664)

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2)WE know i=cis(pi/2)=ei(pi/2)
logii=ilogi=ilog(ei(pi/2))=i2(pi/2)= - pi/2
So sin(logii)=sin(-pi/2)= -1= -1+0
So a= -1 b=0
Also cos(logii)=cos(-pi/2)=0
Hope u r clear!!!

ADARSH
NITK Surathkal

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Dear Sarvpriye,

Experts answer only one question at a time. Please let us know which of these questions you want to be answered first and then post other queries on a new page

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No response from the post owner, removing question from the pending queue.

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