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Community Discussion Question: Complex no.

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25 May 2008 09:07:23 IST

Subject: Complex no.

swarit_08 (16)

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##

if z = i^i^i^i..... and given that z = a+ib i = rt(-1)

then find mod. z

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25 May 2008 10:35:37 IST

Subject: Re:Complex no.

priyesh (1605)

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i^i^i^i........... = a + ib

=> ${i}^{a+ib}$ = a + ib

=> ${e}^{i(\pi/2)(a+ib)}$ = a + ib

=> $\frac{{e}^{i\pi a/2}}{{e}^{\pi b/2}}$ = a + ib

so mod z = ${e}^{-\pi b/2}$

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this reply: 5 points (with 1 Olaaa!! Perrrfect answer.

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