IIT JEE , AIEEE Forum - Mathematics , Algebra

agent007

if z = re^i(thetha) then Ie^izI = ?

rajat

let z = a + ib = rcos(theta) + i rsin(theta)......................1

then e^iz = e^(ia - b) = e^ia/e^b

therefore ,its mod. = 1 / e^b

from "1" b = rsin(theta)

therefor Ie^izI = e^(-rsin(theta))

do rate me if i am ryt !!

agent007

nice job dude, the answer is correct.

but before i rate you just tell me how did find e^ia/e^b ?

rajat

if u mean how did i find the modulus,then

e^ia is a complex number and its mod. = 1

and e^b is a real number so its mod. is equal to the number itself

and use the property Iz1/z2I = Iz1I / Iz2I

now atleast rate me !!!

agent007

here is the rate and don't forget to check your nudge book.

thanks again