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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: complex nos - 2
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priyesh (1515)

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Let Z(,) = cos + eisin  (,  R, i = -1 ), then the range of values of modulus of  Z(,2) as  varies , is
 
A) [ 2 , 3]                 B) [1,2]
 
C) [ 1/3 , 2/3]          D) [ 1/2 , 3/2]

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priyesh (1515)

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someone pls solve

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nadeemoidu (1174)

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D)
Z(\theta , 2\theta ) = \cos \theta + e^{i2\theta} \sin \theta

 = \cos \theta + (\cos 2\theta+ i \sin 2\theta ) \sin \theta

|Z|^2 = ( \cos \theta + \cos 2 \theta \sin \theta ) ^2 + (\sin 2 \theta \sin\theta)^2

Now simplify ,
|Z|^2 = 1 + \frac{\sin 4 \theta }{2}

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priyesh (1515)

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Thanks nadeemoidu

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