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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Dec 2007 21:32:20 IST
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A+ib=i^i^i.....infinity
then A^2+b^2=?
is it e^-piB/2
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16 Dec 2007 23:38:15 IST
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the answer is
e^-(b pi)
this is a simple 1 u need solution or just answer?
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16 Dec 2007 23:39:36 IST
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tnx..no ill try myself first
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You must remember : ii = e-pi/2
form the given relation : A+iB = iA+iB
A+iB = iA.iiB
A+iB = iA.e-(pi/2)B
Now take modulus on both sides and square :
| A+iB |2 = | iA|2.|e-(pi/2)B|2
A2 + B2 = e-pi.B
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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