
|
| physics chemistry maths science forums |
|
|
|
| |
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Feb 2008 11:15:03 IST
|
|
|
z=ilog(2-root3),then cosz=
|
satyabharadwaja |
|
|
|
|
|
|
|
cosz= (eiz+ei(-z))/2 iz= i*i log(2-  3)= -log(2-  3) so cosz= ((1/(2-  3))+(2-  3)))/2 = (2+  3+2-  3)/2 =2
|
this reply: 10 points
(with 2 
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|