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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 12:45:39 IST
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if z1&z2 are 2 non zero complex no.ssuch that /z1+z2/2=/z1/2+/z2/2,then
(a)z1z2' is purely imaginary (b)z1/z2 is purely imaginary
(c)z1z2'+z1'z2=0 (d)o,z1,z2 are the vertices of a right angled
triangle
pls answer with explanation
here ' represents conjugate
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31 Mar 2008 15:24:34 IST
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just do it by applying knowlege of vectors..
/a+b/ ^2 = /a/^2 + /b/^2 + 2/a//b/cos@ ...
now frm given equation u see tht...
2/a//b/cos@ = 0...
so cos@ = 0
@ = pi / 2... where @ is angle b/w vectors...
now ..see the options..
we know arg(z1) - arg(z2) = arg(z1/z2) = pi/2..
so vector z1/z2 is purely imaginary..
now solve others a) d) r also correct..
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Diamonds r formed under greatest pressures..
so r the champs.
Kriteesh..
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31 Mar 2008 15:26:35 IST
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the ans is "c" coz.../z1+z2/2=/z1/2+/z2/2+z1z2'+z1'z2
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31 Mar 2008 15:28:20 IST
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oops!! missed tht..
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Diamonds r formed under greatest pressures..
so r the champs.
Kriteesh..
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31 Mar 2008 15:36:20 IST
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is the answer (a) (c) (d) ? edit=== didnt see it solved :\
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* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
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31 Mar 2008 15:48:38 IST
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all are correct ie answer is a,b,c,d
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