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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Jul 2007 09:27:29 IST
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A,B and C are points represented by complex numbers respectively. If the circumcentre of the triangle ABC lies at the origin and the altitude AD of the triangle meets circumcircle again at P, then P represents the complex number
(A) (B) (C) (D) none of these.
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Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm
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take points a,b,c as 1,0 , 0,-1 and 0,1 automatically point P comes as -1,0. so the answer is a.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Jul 2007 22:14:47 IST
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P LIES ON THE CIRCUMCIRCLE, DIAMETRICALLY OPPOSITE TOA(Z1).HENCE ,IT IS THE RE4FLECTION OF A ABOUT ORIGIN .THUS, IF Z1=X+iY,THEN, P=-X-iY.HENCE, P IS GIVEN BY -Z1.CORRECT OPTION IS NONE OF THESE.
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