IIT JEE , AIEEE Forum - Mathematics , Algebra

hsbhatt

I liked this one. It's easy but fun doing:

$\text{Solve for positive integers a,b,c,d satisfying} \\ \\ \frac {37} {13} = a + \frac {1}{\frac{b+ \frac{1} {c+ \frac{1} {d}}}}$

The continued fractions end at d. That line is extra (some prob with my tex coding)

nadeemoidu

$(1/x ) < 1 \quad if \quad x > 1$

So that means that
$a = [ \frac{37}{13} ]$ where [] is the greatest integer function.

a = 2

$b+ \frac{1} { c + \frac {1}{d}} = \frac{13}{11}$

b=1

${ c + \frac {1}{d} = \frac{11}{2}$

c= 5

d =2

computer001

a=2,b=1,c=5,d=2

computer001

@ nadeem:oh sorry din c tht u already answered

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