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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 May 2007 14:53:23 IST
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 If D= a 1x+ b 1y a 2x+b 2y a 3x+b 3y then D= b1x+a1y b2x+a2y b3x+a3y b1x+a1 b2x+a2 b3x+a3 a. x2 + y 2 b. a1a2a3 c. b1b2b3 d. 0 D=determinant
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9 May 2007 15:31:50 IST
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Can u plz check your question once more ????
Sorry for the inconvinience..........
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9 May 2007 15:52:42 IST
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oops SORRY! I've corrected it!
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9 May 2007 16:26:06 IST
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Hmm.........i am not sure.but here;s my solution....... The given condition should be satisfied to all values of x and y. As a short cut method, put x=y or put x=y=1 The determinant value will become "0" as all the 3 rows are identical. hence,the answer is "0" I am NOT sure of the answer,plz correct me if I am wrong.
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9 May 2007 16:33:02 IST
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your answer is correct karthik but here is the solution:
given DET=product of 2 dets which are
a1 b1 0 x y 0
a2 b2 0 and y x 0
a3 b3 0 1 x 0 hence the answer is 0.
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9 May 2007 16:36:58 IST
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hey karthik,wen u subst. x=y and the rows or colums of a determinant becum proportional(in dis case dey becum equal n so u get 0)den it means dat (x-y) is a root of the determinant... hey plzz if i'm rong ,corect me...coz dis is wat i red.. n if i'm ryt,plzz rate me...
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10 May 2007 19:25:23 IST
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yes,u r ryt.......but that is not asked here....... .......and there is no need of it here.
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IF U THINK U CAN, U CAN........IF U THINK U CAN'T, U CAN'T.........
BE THE BEST OF WHAT EVER YOU ARE!!!
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