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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Apr 2007 21:34:02 IST
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Dear Experts ,please solve this deteminant and bring the answer in simplified form.AND PLEASE SOLVE THIS USING THE PROPERTIES. | x y z| | y x y| | z y x| (NOTE:These are not a broken lines.They are continuous lines for showing the determinant .)
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Ken
From: UNITED STATES, Green Bay, Wisconsin
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Apr 2007 22:24:58 IST
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(x-z)(x^2+xy-2y^2)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Apr 2007 22:43:31 IST
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hey it is (x-z)(x^2+xZ-2y^2)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Apr 2007 22:44:47 IST
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C1 -> C1-C3 TAKE OUT (X-Z) FROM R1
THEN r1-> R1 + R3 THEN EXPAND ALONG C1
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Apr 2007 15:04:52 IST
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C1-C3 ->C1 |x-z y z | |0 x y | |z-x y x | = (x-z) |1 y z | |0 x y | |-1 y x| R1+R3->R1 = (x-z) | 0 2y z+x | | 0 x y | |-1 y x | =(x-z) (-1) (2y2 ?xz -x2) =(x-z) (x2 +xz ?2y2) (NOTE:These are not a broken lines.They are continuous lines for showing the determinant .)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Apr 2007 15:29:08 IST
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I think the answer is (x-z)(x^2 +xz-2y^2) (C1)prime=C1-C3 | x-z y z | | 0 x y | | z-x y x| Take (x-z) from C1 | 1 y z | (x-z) | 0 x y | |-1 y x | Let R1(prime)= R1+R3 |0 2y x+z | (x-z) |0 x y | |-1 y x | (x-z)[-1(2y^2-x(x+z))] (x-z)[x^2 +xz -2y^2] | (NOTE:These are not a broken lines.They are continuous lines for showing the determinant .) | | Please rate for my efforts if satisfactory or inform me if I am wrong. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Apr 2007 21:00:43 IST
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hey dats wat i hv been doin....,, lol...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Apr 2007 20:49:47 IST
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Hey guys and respected expert!!!!!!!!!!! You all are correct and thank you all to show me the correct way of solving this determinant using the properties.
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Ken
From: UNITED STATES, Green Bay, Wisconsin
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