
follow the steps:
bc=x,ca=y,ab=z.
we get>>>>>

out side determinant is 1/xyz.
take out (x+y+z)^2 common out.
apply C3=C3-C1-C2
R1=R1+R2.

U WILL GET TW0 ZEROS AT -2XY POSITIONS
U WILL GET ABOVE BY FOLLOWING STEPS. R1=R1+R3 ... R2=R2+R3.
NOW EXPAND .
U WILL GET A DET OF ORDER 2.

GET THE ANSWER.....SUBSTITUTE THE VALUE OF X,Y,Z.
ANS====2(bc +ca+ +ab)^3
hope u understand the method....
after getting the answer nudge me.
best of luck.
above is d a same question but different variables......
follow the steps:
bc=x,ca=y,ab=z.
we get>>>>>
out side determinant is 1/xyz.
take out (x+y+z)^2 common out.
apply C3=C3-C1-C2
R1=R1+R2.
U WILL GET TW0 ZEROS AT -2XY POSITIONS
U WILL GET ABOVE BY FOLLOWING STEPS. R1=R1+R3 ... R2=R2+R3.
NOW EXPAND .
U WILL GET A DET OF ORDER 2.
GET THE ANSWER.....SUBSTITUTE THE VALUE OF X,Y,Z.
ANS====2(bc +ca+ +ab)^3
hope u understand the method....
after getting the answer nudge me.
best of luck.
above is d a same question but different variables......