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Algebra

vignesh  the cooler version of newton's Avatar
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18 Mar 2009 12:15:37 IST
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determinants, plzz reply .....
None

 plz reply as soon as possible..

 


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saharsha kumar keshkar's Avatar

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18 Mar 2009 15:54:22 IST
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follow the steps:

bc=x,ca=y,ab=z.

we get>>>>>

out side determinant is 1/xyz.

 

take out (x+y+z)^2 common out.

apply C3=C3-C1-C2

R1=R1+R2.

U WILL GET TW0 ZEROS AT -2XY POSITIONS

U WILL GET ABOVE  BY FOLLOWING STEPS.   R1=R1+R3   ... R2=R2+R3.

NOW EXPAND .

U WILL GET A DET OF ORDER 2.

GET THE ANSWER.....SUBSTITUTE THE VALUE OF X,Y,Z.

ANS====2(bc +ca+ +ab)^3

hope u understand the method....

after getting the answer nudge me.

best of luck.

above is d a same question but different variables...... 

 

saharsha kumar keshkar's Avatar

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18 Mar 2009 16:03:10 IST
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if steps are not clear then nudge me!!!!!!!!!!!!!

Mirka's Avatar

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18 Mar 2009 16:41:25 IST
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@ vignesh-cool newton :

The question shud have been 

 

 

 

there is one more way how you can do this .... Wait, im loading my solution

 

 

Mirka's Avatar

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18 Mar 2009 16:44:52 IST
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akshay A NEW BEGINNING...'s Avatar

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18 Mar 2009 17:30:34 IST
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A solved example of NCERT u can check it out form there....also mrika has it right.
Mirka's Avatar

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18 Mar 2009 17:34:16 IST
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@ akshay : d ncert eg. had xy, yz and xz instead of x^2, y^2, z^2 ... ... but ya ... method's kinda similar !
saharsha kumar keshkar's Avatar

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18 Mar 2009 17:35:24 IST
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nice and systematic by mirka........

mine is not visible clear..............

vignesh  the cooler version of newton's Avatar

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18 Mar 2009 18:52:56 IST
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thanx a lot mirka.. sorry 4 uploading right han part wrong... thanx...
rakesh  bokaro's Avatar

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Joined: 15 Jul 2008
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18 Mar 2009 18:53:04 IST
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rate deserving solutions!!!!!!!!!

 




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