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Comments (6)
clearly, alpha + beta + gama = 0  (i)
alpha^{2} + beta^{2} + gama^{2} = 1
alpha x beta + beta x gama + gama x alpha = 1
alpha x beta x gama = 1
So,on dividing alpha x beta + beta x gama + gama x alpha by alpha x beta x gama we get,
1/alpha + 1/beta + 1/gama = 1
Adding 3 to both the sides we get
(1 + alpha)/alpha + (1 + beta)/beta + (1 + gama)/gama = 2
But what next to do??????????
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