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netkid07 (2009)

Blazing goIITian

Olaaa!! Perrrfect answer. 359  bad job dude!! I dont approve of this answer! 2  [470 rates]

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if x,y,z are distinct n real then the expression x^2+4y^2+9z^2-6yz-3zx-2xy is

non-negative
non-positive
zero
none of these.........

ab mera mazak mat udana.....coz i m new to quadratic..........n also i hav to study it myself coz i don't go to any coaching

Who says nothing is impossible.

I've been doing nothing for years !!..............


I know KUNG FU KARATE
and 47 other dangerous words.............

    
hsbhatt (5015)

Forum Expert Blazing goIITian

Olaaa!! Perrrfect answer. 945  [1090 rates]

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Let a = x, b = 2y and c = 3z.
 
The given expression becomes
a2+b2+c2-ab-bc-ca = 0.5*(2a2+2b2+2c2-2ab-2bc-2ca)
 
= 0.5*[(a-b)2+(b-c)2+(c-a)2] >= 0. i.e. non-negative

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 this reply: 15 points  (with Olaaa!! Perrrfect answer.   in 3 votes )   [?]
 
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