IIT JEE , AIEEE Forum - Mathematics , Algebra - easy question....but stil cant gt d correct answer! pls help!

sumedha

The letters of the word ?SURITI? are written in all possible orders and these words are written out as in a dictionary. Find the rank of the word ?SURITI?.

mukulss

kk i have tried:

ty get: SURITI

write in alphabatical order:

I I R S T U

now starting with I:
I _ _ _ _ _         5! words(leave them)

again ,
no use of starting with I

now starting with R

R _ _ _ _ _     no of words to be left:   5!/2!

u get now:

S I I _ _ _   no of words to be left: 3!

we get:

SR _ _ _ _ no of words to be left: 4!/2!

again we get:

ST _ _ _ _ no of words to be left: 4!/2!

ohohohh,

again we get:
SUI _ _ _ no of words to be left: 3!

now:

SUR I I T to be left 1

finally we get:

S U R I T I

oh now come on yaar,
add plaese aapneaap se kar lena,
i just got tired of writing that much:

u will fimallly get teh answer........

sumedha

hey jus chek dis out

SURITI......

to begin with .......

no of words startin wid I= 5!

no of words startin wid R=5!/2!

now words startin wid S:

SI_ _ _ this can be formd in 3! ways

next wud b SR_ _ _ this can b formd in 3!/2! ways

no of words beginin wid ST_ _ _ can b formd in 3!/2! ways

now we hav words begini wid SUI_ _ which can b formd in 2! ways...

next wud b SURIIT

den SURITI

so d rank of of d word SURITI shud b 5!+5!/2!+3!+3!/2!+3!/2!+2!+2th word!!!

pls tel me if dis is correct!!!!!

priyesh

hi

the soln is as following

1.the total no. of words are 6!/2! = 360

2.now let's count the words which wil come before suriti which are words starting with i,r,si,sr,st,sui

3.words starting with i=5!;r=5!/2!;total=60+120=180

4.words starting with si=4!;sr=4!/2!;st=4!/2!;total=24+12+12=48

5.words starting with sui are 3!=6

6.adding all the bold values we get 234

7.now two words are left suriit & suriti but suriit will be placed before suriti there fore suriit will get ranked 235 & suriti 236.

THEREFORE THE RANK OF THE WORD SURITI IS 236

elastiboysai

priyesh is rt

i also got 236

mukulss

hey what abt my solution,
am i correct?????

apurva91

SURITI

ARRANGE THEM

IIRSTU

I _ _ _ _ _=5! WAYS
NOW IGNORE ANOTHER I
THEN FOR R
R_ _ _ _ _=5!/2! SINCE THERE ARE 2 I THEREFORE IT IS DIVIDED BY 2!

THEN FOR S SINCE IT IS THE REQUIRED ALPHABET THEREFORE MOVE ON AND START THE SEQUENCE AGAIN FOR THE 2ND PLACE

SI_ _ _ _ =4!
IGNORE ANOTHER I NOW
SR_ _ _ _=4!
ST_ _ _ _=4!
SUI_ _ _ _=4!
SURII_=1!
SURITI

ADD THEM N U HAVE THE RESULT

RATE ME IF IT WAS USEFUL.........

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