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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Jun 2007 23:13:33 IST
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there r x boxes in which a some dolls wree placed such that each box contains the same no of dolls and no dolls were left unpacked,if the no of boxes were reduced by 3 then the dolls packed and 5 dolls were left unpacked then find the total no of boxes ????
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Jun 2007 23:23:21 IST
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plss!! anyone
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Jun 2007 23:26:22 IST
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i think the question is wrong
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One who questions training, trains himself only at asking questions. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Jun 2007 23:28:44 IST
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wat do u think is wrong in it ??can u expln pls!!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Jun 2007 23:34:31 IST
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since 3 boxes are reduced and now 5 dolls are left unpacked that means those 5 dolls were in those 3 boxes . but according to question each box contains equal no. of dolls. that means each box contained 5/3 dolls. that doesnot look practical so i think there is something wrong with the question
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One who questions training, trains himself only at asking questions. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Jun 2007 23:44:26 IST
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Jun 2007 23:44:45 IST
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no actually after removing three boxes, dolls were repacked in the remaining boxes.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Jun 2007 00:37:54 IST
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Hello flowers_rsss Please check your query once again. akshaybansal' s doubt is right. Let's see it --- Boxes = X and Dolls=Y then in first attemp you put 'n' dolls in each box than n.X = Y .........(1) now in second attemp you have to put Y-5 dolls in X-3 Boxes so the equation becomes n.(X-3) = Y- 5 ........ (2) using (1) n.(X-3) = nX- 5 -3n = -5 or n= 5/3 which is ridiculous. if you try to say that you have put m dolls in second attemp than the eqation becomes m(X-3) = nX-5 or x = (3m-5)/m-n now are you able to get a unique or right solution from it... Please see your query once again and post it correctly.
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flowerssss there is something wrong with the question . it has multiple (INFINITE) answers. try the following no. of boxes no. of dolls in each box 10 4 11 7 13 5 and so on ..... so i think some information in the question is incomplete
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One who questions training, trains himself only at asking questions. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Jun 2007 23:02:48 IST
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Hello akshaybansal Your attemp is good but please check your (i) option once again. Total dolls = 8 * 7 = 56 now reduce the boxes by 3 than boxes are 5 and hence 56/5 gives 11 dolls in each box and only one left. But I am agree with you that question is incomplete.
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