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2 Oct 2011 23:28:13 IST

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f(x)=ax^2+bxt+c=0, f(5)+3f(2)=0,3 is the rootof this equation find the other root.

Mathematics

f(x)=ax^2+bxt+c=0, f(5)+3f(2)=0,3 is the rootof this equation find the other root.

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Manasi

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Joined: 1 Dec 2006

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13 Feb 2012 13:54:48 IST

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f(x)=ax²+bxt+c

f(5)+3f(2)=0

=>[25a+ 5bt +c] + 3[4a+2bt+c] = 0

=>37a + 11bt + 4c= 0 ....................(a)

f(3)=0

=>9a+3bt +c=0 Multilpying both sides by '4'

=>36a + 12bt + 4c = 0 .....................(b)

(b)-(a)

a - bt =0

=>bt =a

=>c=-12a

thrfore, f(x)= ax²+ax-12a

thus f(x) = 0

=> a (x²+x-12) = 0

=> x = 3, -4

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