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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: FINALLY THE ANSWER
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Mr.IITIAN007 (2985)

Blazing goIITian

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Hey guys and gals ! This is the answer of my query post 'Factorial series'.

                    [ j=1 ][ n ] j j . j !

Well what I think, the series practically bursts (neither infinite nor finite but increasing w.r.t a common variable ) as n increases which is absolutely not significant.But if I consider the entire series to be a convergent function f(n) then according to combinatrical reasoning and statistical induction and common variable say j must vary from 1 to n which can exactly be done in terms of  summation.Then I applied the 3rd principle of Game theory to get the answer.But this is an  Olympiad Level question not for IIT standard,I  am sorry to ask such question.It will look weired to all you users. I don't think this can be solved in simpler ways.I have to ask my friends in resonance whether they are just kiding .

Ken
From: UNITED STATES, Green Bay, Wisconsin
    
jaysunantony (171)

Scorching goIITian

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hey......................what's this..........

this is just another way of writing the qn.................cant u seee....???.......

My name is Jaysun Antony.........

Whatever we do............the final decision is God's.......

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Mr.IITIAN007 (2985)

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Well the answer that you gave in 'SIMPLE ONE' forum is also the another  way of writing the question.You generalised the solution there , so as I have done here.Can't you understand..........????..................For any solution of a series involving 'n' you cannot have a perfect answer like 9,1000,875etc.The solution must involve n.For calculations involving A.P,G.P modern science has  generalised terms like the common difference,common ratio,sum upto n terms.For example, in school exams we don't derive the general formula for nth term of an A.P,or nPr or nCr .We  just  put the values given in the question in the formula,understand the problem and get the answer.

Ken
From: UNITED STATES, Green Bay, Wisconsin
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Lolita (31)

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Great answer Ken .

Be cool..............................
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