9/1! + 16/2! + 27/3! +42/4!+.......  is equal to????

plz giv ur xplanations............

nr forst diff in ap so itll be of the form an^2+bn+c Dr is ob n! so you'll get some answer in terms of e on solving!

The general term of the series 9,16,27,42,.... is T_r=2r²+r+6.Hence the sum is

 2r²+r+6r!    =sig 1/(r-1)!+sig 6/r!+sig2r/(r-1)!

                                 =e+6(e-1)+2(e+e)=11e-6

[am i correct?]