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Celestine Preetham's Avatar
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2 May 2008 12:09:09 IST
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find min a + b such that a+11b and a+13b are multiples of 13 and 11 resp. a,b>0
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find min a + b such that a+11b and a+13b are multiples of 13 and 11 resp. a,b>0


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zorro's Avatar

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2 May 2008 12:30:13 IST
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Is the answer 23?
Kirpal Singh's Avatar

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2 May 2008 12:38:23 IST
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No I'm also getting 7.


a+11b = k(13)


a+13b= k'(11)


(a+11b) + 2b =k'(11)


b = k'(11) - k(13) (but b>0)  => b = 9/2 and therefore, a = 5/2


Hence a + b = 7

Celestine Preetham's Avatar

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2 May 2008 13:21:54 IST
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Zorro how are u saying its 23
James Bond's Avatar

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2 May 2008 13:52:50 IST
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@ KIRPAL.....plz make a correction....

zorro's Avatar

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2 May 2008 13:59:40 IST
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let a + b = y ........(1)



now,



a + 11b = 13x............(2)



and a + 13b = 11z ..............(3)



where x and z r integeres >=1



sovle above 3 equations to get



y = 78x - 55z

therefore



a + b = 78x - 55z



for min value x=z=1



so, min(a+b ) = 23

 

Celestine Preetham's Avatar

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2 May 2008 14:00:55 IST
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u want me to give ans or let others try ???
Celestine Preetham's Avatar

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2 May 2008 14:04:49 IST
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gud try Zorro
But I forgot to mention that a,b are natural nos
if u put a+b as 23 ull get a,b asfractions
TRY NOW
zorro's Avatar

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2 May 2008 14:16:12 IST
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no such values of a and b exists..



hence no solution.


I think soo..


what's the answer?????????

Celestine Preetham's Avatar

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2 May 2008 14:31:17 IST
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no solution exists
dont give up so soon
I took more than half an hour to figure out the ans
Celestine Preetham's Avatar

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2 May 2008 14:31:35 IST
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solution exists
dont give up so soon
I took more than half an hour to figure out the ans
zorro's Avatar

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2 May 2008 14:35:58 IST
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in equation a + b = 78x - 55z


substitute diff values of x and z and see for which values a and b are natural nos.

and I m not having so much patience to solve like this..
so, will not do this..

hehe
Celestine Preetham's Avatar

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2 May 2008 14:47:22 IST
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No Zorro I would say your method of approch is wrong
There is a more intelligent way of solving this
HE HE
Kirpal Singh's Avatar

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2 May 2008 16:05:26 IST
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min. (a+b) = 56

Kirpal Singh's Avatar

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2 May 2008 16:16:54 IST
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Given : a+11b=k(13) - (i)
a+13b=k'(11) - (ii)
and, (a,b) belongs to Natural no.'s
Proof : (a+11b)+2b=k'(11)
b=[k'(11)-k(13)]/2
Therefore, b(min.)=10 [because, b belongs to Natural no.)
Now, for a(min.)=46 eq. (i) & (ii) are satisfied
Hence, a+b(min.)=46+10=56
Celestine Preetham's Avatar

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2 May 2008 16:39:11 IST
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sorry kirpal
ur reasoning that b min is 10 is wrong
Kirpal Singh's Avatar

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2 May 2008 16:53:34 IST
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Acc. to u reasoning that b min is 10 is wrong. Could u pls. explain me how.
Celestine Preetham's Avatar

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2 May 2008 17:17:06 IST
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well bmin is not 10


It is actually ....................... Youwant me to tell u ???


ne way   Kirpal


could u please explain in detail how u r telling bmin is 10 . In that process u may find ur error

Hari Shankar's Avatar

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2 May 2008 17:46:30 IST
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My attempt:




 


a+11b = 13  




 


a+13b = 11




 


Eliminating b we get 2a = 169  - 121  




 


Also 2b = 11 - 13




 


Hence 2(a+b) = 156 - 110


1 and 2, and  11 - 13   0 and  and  are of the same parity and hence the least difference is 2


give up!

kislay kumar's Avatar

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5 Jun 2008 21:55:55 IST
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 no value of a+B exists as such.....


2a = 169  - 121  .....................................1


2b = 11 - 13 ..................................................2


a+b = 78 - 55 .................................................3


since a and b are natural no.s(as mentioned by author of this ques)...from eqn 1


    169  121 


=>  (121/169) 


=> (1.18) .....................................4


 


also from eqn.2


11  13 


 


=>  (13/11) 


=>  (1.39) ..................................5


 


thus from eqn (4) and (5) no such value of a and b exists..


 




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