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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: find n
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maha (0)

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x1,x2,......xn be n observations... then value of n is

    

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feynmann (2472)

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Using Caucy-Schwarz inequality we can only say that n>= 80^2/400=16

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sboosy (3065)

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 \mbox{Another method would be to use} \\ \\ \mbox{AM of mth power} \ > \ \mbox{mth power of AM for} \ m>1 \\ \\ \mbox{By that} \ \frac{x_1^2+x_2^2+.....x_n^2}{n} \geq \left(\frac{x_1+x_2+...x_n}{n}\right)^2 \\ \\ \Rightarrow \frac{400}{n} \geq \frac{80^2}{n^2} \\ \\ \Rightarrow n\geq 16

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thedumbheadwithnobrain (887)

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\frac{x_1^2+x_2^2....x_n^2}{n}\ge \left(\frac{x_1+x_2+....x_n}{n}\right)^2\\\frac{400}{n}\ge\frac{80^2}{n^2}\\\\\Rightarrow n\ge 16

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