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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: find the 7th root of 7^(7^7)
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kishlaymishra (0)

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find the 7th root of 7^(7^7)
    
aditya_arora04 (1072)

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7^7^6  ????

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sandy1990 (12)

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scroll down

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bhavanawannastudy (67)

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i agree with aditya, 7^7^6
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RyuAmakusa (329)

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[ 7]77.77.77.77.77.77.77 = 77 is it not the ans. i did not see the ( )
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sandy1990 (12)

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ans is 7^7
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sandy1990 (12)

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check it with anyone
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digs2digi (157)

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yeah,sandy is rite
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feynmann (1548)

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nope !!
 
 take ( 7^7 ) = m
 
so we are to find ( 7^m) ^( 1/7 )
 
                        = 7 ^ ( 7 ^7 /7 )
 
                         = 7^ ( 7^6 )
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nadeemoidu (1174)

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7^(7^7) and (7^7)^7 are different .

(7^7)^7 = 7^49 . The seventh root of this no. is 7^7.

But the question asked is 7^(7^7)
It's 7th root is 7^[(7^7)/7] which is equal to 7^(7^6)
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sandy1990 (12)

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learn prop of exponentials
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digs2digi (157)

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yeah sry.its 7^(7^6)
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RyuAmakusa (329)

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i never notised the ( )
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sandy1990 (12)

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no it is 7^7
since 7th root
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sboosy (2860)

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7^{(7^7)} = 7^k \ \mbox{where} \ k=7^7 \\ \\ \mbox{Taking seventh root we get} \ 7^{\frac{k}{7}} \\ \\ \frac{k}{7} = \frac{7^7}{7} = 7^6 \\ \\ \mbox{which gives} \ 7^{(7^6)}
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