IIT JEE , AIEEE Forum - Mathematics , Algebra

mathiit

If log 3=0.4771213

then find

sachinguptaiit

rudra.panda

Here is my solution:

$\log ((2.7)^3\times(0.81)^\frac{4}{5}\div(90)^\frac{5}{4})\\\\=3 \log \frac{27}{10}+\frac{4}{5}\log \frac{81}{100}-\frac{5}{4}\log 90\\\\=3(\log 3^3-1)+\frac{4}{5}(\log 3^4 -2)-\frac{5}{4}(\log 3^2+1)\\\\=\left(9+\frac{16}{5}-\frac{5}{2}\right)\log 3- \left(3+\frac{8}{5}+\frac{5}{4}\right)\\\\=\frac{97}{10}\log 3- \frac{117}{20}\\\\=4.6280766-5.85\\\\= -1.2219234$

sriram.a

Rudra dona u think 3rd last step its 9.7log3-5(117/20)

rudra.panda

Sorry typing error. Thanks for correcting it.

Ask & Discuss Questions with Community & Experts