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19 May 2012 18:12:43 IST

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find the value of i^i

Engineering Entrance , JEE Main , JEE Advanced , Mathematics , Algebra

someone has asked me this question

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BASTIN JOSE

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19 May 2012 18:18:09 IST

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Its one value is e^(-i pi/2)

BASTIN JOSE

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20 May 2012 17:55:15 IST

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sorry it is e^-pi/2

pooja garg

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20 May 2012 17:58:37 IST

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e^(-pi/2).....................take i =e^(pi/2)............ur questn now becomes...............e^(i^2)pi/2...............and i^2 = - 1......................hence d result.....................hit like if it hlpd

viswanathan

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21 May 2012 15:04:23 IST

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@pooja,its confusing please explain i^i=(e^pi/2)^(e^pi/2)

BASTIN JOSE

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21 May 2012 15:16:23 IST

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i=0+1i

cos theta=0

sin theta=1

therefore theta=pi/2

r=1

i=1e^(i pi/2)

i^i={e^(i pi/2)}^i

=e^(i*i pi/2)

=e^(-1 pi/2)

=e^(-pi/2)

Did you understand ??????

viswanathan

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22 May 2012 19:43:18 IST

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super

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