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armaan (238)

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find the number of solutions of y= lsinlxll = x +lxl
 were x [-2,2]

its hard to manage cuZ everyday zz a challenge... n i am slipping .., can't loose up balance ..
i Try nOh to panic..!
    
akhil_o (2704)

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draw a graph..
it comes out to be the same graph as that of
|sin x|
now
x+|x|, for x>0, it is y=2x
for x<0, y=0

at every n(pi), value of f(x)=|sin x|=0
so -pi, -2 pi and 0 are solutions

for y=2x and y= |sin x|
sin x <=x for x>0
so sin x< 2x
so no solution in first quadrant

so only 3 solns

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armaan (238)

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no boss...the answer is 1 soln...!

its hard to manage cuZ everyday zz a challenge... n i am slipping .., can't loose up balance ..
i Try nOh to panic..!
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akhil_o (2704)

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then explain my mistake in these 3 points here...


" Always remember money isn't everything but make sure you have made a lot of it before talking such nonsense!"
- Bill Gates
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krishna.gopal (2149)

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I think akhil's answer is right

Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi
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computer001 (1847)

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2 explain akhil's answer u dun need graph...0,-pi,-2pi are obvious solutions

Nitwit Blubber Odment Tweak
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