Algebra

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for cricket fans who luv maths......
Engineering Entrance , JEE Main , JEE Main & Advanced , Mathematics , Algebra

IND VS AUS.wat are the ways in  which m.s dhoni can score 30 runs in the last over....provided every ball is legal.and no extras are conceded???remember gilchrist is the wicket keeper......



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Blazing goIITian

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2 Apr 2012 15:51:38 IST
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there should be minimum 3 sixes to score 30 runs in an over ..........now if three six are hitted then the total no. of ways are(three four also)=6C3..now if 4 sixes are hitted(remaining 6 runs 4,2 or 6,0 or 3,3)=6C4{2!+2!+1}...now if five six are hitt(remaining 0)=6C5.

Blazing goIITian

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2 Apr 2012 15:53:37 IST
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so the the total no. of ways=6c3+6c4{2!+2!+1}+6c5
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2 Apr 2012 16:33:31 IST
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wrong..
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2 Apr 2012 16:54:30 IST
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well i guess the solution by tarun garg is rit..if the condition of hitting the helmet behind the keeper is not considered..but if it is considered than one more way is added when on all the six balls, the ball hits the helmet behing the keeper
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2 Apr 2012 16:54:50 IST
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well i guess the solution by tarun garg is rit..if the condition of hitting the helmet behind the keeper is not considered..but if it is considered than one more way is added when on all the six balls, the ball hits the helmet behing the keeper
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2 Apr 2012 16:55:38 IST
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on hitting the helmet behind the keeper.. 5 run is consided
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2 Apr 2012 17:02:38 IST
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71
ronnie's Avatar

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2 Apr 2012 23:30:52 IST
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KARTIK IS RYT..
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2 Apr 2012 23:33:57 IST
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ACTUALLY he did mistake in the first step while doing combination....

Blazing goIITian

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3 Apr 2012 07:22:25 IST
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where
ronnie's Avatar

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3 Apr 2012 14:31:51 IST
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IT SHUD HAV BEEN 6!/3!3!

Blazing goIITian

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3 Apr 2012 14:36:07 IST
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so it is 6c3

Blazing goIITian

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3 Apr 2012 14:38:04 IST
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i got it it should be 6c3+6!/4!{2!+2!+1}+6!/5!

Blazing goIITian

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3 Apr 2012 14:39:28 IST
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i am confused
ronnie's Avatar

Scorching goIITian

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3 Apr 2012 14:41:50 IST
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SRY I MADE A MISTAKE...U TOOK THE 666660 ARRANGEMENT TWICE

Blazing goIITian

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3 Apr 2012 15:05:17 IST
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nops

Blazing goIITian

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3 Apr 2012 15:05:50 IST
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pls write the whole solution
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3 Apr 2012 21:56:59 IST
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there should be minimum 3 sixes to score 30 runs in an over ..........now if three six are hitted then the total no. of ways are(three four also)=6C3..now if 4 sixes are hitted(remaining 6 runs 4,2 or 6,0 or 3,3)=6C4{2!+2!+1}...now if five six are hitt(remaining 0)=6C5.see ur mistake i hav underlynd it.

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5 Apr 2012 09:30:26 IST
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tarun is write



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