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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Jun 2007 13:04:50 IST
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function =>log2log3log4(x) what is the domain & range of this function?
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There are two ways to live: you can live as if nothing is a miracle; you can live as if everything is a miracle.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Jun 2007 13:20:02 IST
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DOMAIN x  (4,  ) RANGE x  [0,  )
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Jun 2007 13:22:32 IST
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the domain is 4 to infinity,range 0 to infinity!
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domain=(4,infinity) range=(0,infinity)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Jun 2007 13:31:13 IST
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how do you find it explane again
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There are two ways to live: you can live as if nothing is a miracle; you can live as if everything is a miracle.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Jun 2007 15:17:28 IST
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hey the exp.is here fr the function f(x)=log2 log3 log 4(x) to b defined firstly fr log4(x) 2 b defined x>0 then fr log 2(y) 2 b defined ...........whr y=log 3 log 4(x) y>0..............bcoz we know the no inside log has2 b >0 so log3log4(x)>0 => log4(x)>1 =>x>4 so finally domain is x>4 fr range:------ since the base is >1 nd also the no inside log is>1 (>4) so the ans is always a +ve no thus range is 0 to infinity hope u got it do rate my efforts.............
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