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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: functions;
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[Post New]19 Jul 2008 13:26:28 IST
    Subject: functions;
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sahana_2193 (26)

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find the range of the function  defined by y=2x/(x2+1)
    
[Post New]19 Jul 2008 14:15:45 IST
    Subject: functions;
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spideyunlimited (3912)

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[-1,1]
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[Post New]19 Jul 2008 14:36:52 IST
    Subject: functions;
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mukulaish (238)

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Y=2X/X^2+1

x^2y + y=2x

x^2 y -2x+y=0
x={2+(4-4y^2)^1/2}/2
x=1+root(1-y^2)

for x to be real 1-y2>0
y2-1<0
y belongs to [-1,1]



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