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Algebra

AIR 538 Asish's Avatar
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6 Jun 2009 10:11:58 IST
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functions all over the place
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Q1. If f(x) is a polynomial satisfying the condition f(x).f(1/x) = f(x) + f(1/x) and f(2) = 9 then

(a) 2f(4) = 3f(6)  ..... (b) 14f(1) = f(3) ....... (c) 9f(3) = 2f(5) ........ (d) f(10) = f(11)

 

Q2. Let g(x) be a polynomial satisfying g(x).g(y) = g(x)+g(y)+g(xy)-2 for all x,y belong to R and g(1) is no tequal to 1. If g(3) = 10 then find the value of g(5)

 

Q3. Let f be a real valued function. If for a given positive constant p,

f(x+p) = 7 + [2007 - 147f(x) + 21(f(x))2 - (f(x))3]. Prove that f(x) is periodic and find its period

 

Q4. The function f(x) satisfies f(x+p) + f(x-p) = 31/2f(x), for all x belonging to R, p>0 . prove that f(x) is periodic and find its period


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akash93's Avatar

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Joined: 21 Nov 2008
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6 Jun 2009 12:42:07 IST
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4.

replace x by x+p n then by x-p

add (1) n (2)

.....(3)

replace x by x+2p

add (3) n (4)

replace x by x+2p

..... (5)

replace x by x+12p

from 5

hence the period of f(x) is 12p

 

PLz rate

 

6 Jun 2009 12:47:24 IST
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for first two questions use RHD method n substitute the condition given in question to solve it...

New kid on the Block

Joined: 6 Jun 2009
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6 Jun 2009 13:03:19 IST
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1) f(x)= anxn + an-1xn-1 +....a0

we have, (anxn + an-1xn-1 +....a0)*(an(1/x)n + an-1(1/x)n-1 +....a0)

= (anxn + an-1xn-1 +....a0) + (an(1/x)n + an-1(1/x)n-1 +....a0)


New kid on the Block

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6 Jun 2009 13:03:56 IST
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1) f(x)= anxn + an-1xn-1 +....a0

we have, (anxn + an-1xn-1 +....a0)*(an(1/x)n + an-1(1/x)n-1 +....a0)

= (anxn + an-1xn-1 +....a0) + (an(1/x)n + an-1(1/x)n-1 +....a0)


New kid on the Block

Joined: 6 Jun 2009
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6 Jun 2009 13:05:02 IST
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AIR 538 Asish's Avatar

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6 Jun 2009 17:09:48 IST
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what is the RHD method? new to this chapter
Mirka's Avatar

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7 Jun 2009 15:32:08 IST
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For the first one, remember the following results :

 

 

Given that f(2) = 9

 

This means that the sign between 1 and xn is +ve and n = 3

 

So, f(x) = 1 + x3

 

Answer will be Option B .... 14 f(1) = f(3)

 

 

Mirka's Avatar

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7 Jun 2009 15:46:37 IST
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Second Qsn

 

x = y = 1 :

 

let y = 1/x

 

 

 

sign must be +ve and n = 2

Thus,  g(x) =  1 + x2

 

g(5) = 1 + 25 = 26

 

 

AIR 538 Asish's Avatar

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7 Jun 2009 15:47:43 IST
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thx mirka
Mirka's Avatar

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7 Jun 2009 15:49:22 IST
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ur welcome ....

 

4th one

 

Similar to this Qsn (with 1 in place of p) but method d same  

 

http://www.goiit.com/posts/list/trignometry-period-913117.htm

 

 

 

See the trigo method by ankit there....

 

Mirka's Avatar

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7 Jun 2009 17:19:06 IST
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The third one, i simplified upto a point ....

 

 

 

hmm... now, how do we proceed ??

 

 

Soumik's Avatar

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7 Jun 2009 23:05:19 IST
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Is the 3rd qsn's period 2p?

AIR 538 Asish's Avatar

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8 Jun 2009 09:04:04 IST
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yes soumik



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