Home » Ask & Discuss » Mathematics. » Algebra « Back to Discussion

Algebra

Scorching goIITian

Joined:	25 Jan 2009
Post:	246

8 Mar 2009 16:25:16 IST

0 People liked this

358

Geometric progression ?

None

Geometric progression ?

Share this article on:

Comments (3)

Anirudh Kumar

Scorching goIITian

Joined: 25 Jan 2009

Posts: 246

8 Mar 2009 16:27:13 IST

Like 0 people liked this

if r<1 and psotive and m is a positive integer, show that

(2m+1)r^m(1-r)<1-r^2m+1. hence showthat nrⁿ is indefinitely small when n is indefinitely great.

rahul gaadhe

Cool goIITian

Joined: 21 Jan 2009

Posts: 90

8 Mar 2009 21:24:10 IST

Like 1 people liked this

for any positive integer n

0<nrⁿ<(1-r²ⁿ⁺¹)n\(1-r)(2m+1)

taking

0< nrⁿ < (1-r²ⁿ⁺¹)n\(1-r)(2m+1)

on solving the right hand limit (by l-hosp.),

we get 0< nrⁿ<0

therefore nrⁿ=0

Anirudh Kumar

Scorching goIITian

Joined: 25 Jan 2009

Posts: 246

9 Mar 2009 07:58:40 IST

Like 0 people liked this

is there any other way than calculas.

Quick Reply

Reply

	Some HTML allowed.
	Keep your comments above the belt or risk having them deleted.
	Signup for a avatar to have your pictures show up by your comment
	If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team

Free Sign Up!

Preparing for IIT-JEE ?

Arihant Revision Package for IIT JEE - Books, Practice Tests + Rank Predictor

@ INR 1,995/-

For Quick Info

Find Posts by Topics

Physics.

Topics

9390

20086

3671

2185

7614

2826

2634

Mathematics.

Chemistry.

Biology

Institutes

Parents

Board

Fun Zone