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6 Aug 2009 11:45:05 IST
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given log2= 0.301 evaluate log 1000/256
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given log2= 0.301 evaluate log 1000/256


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Tanveer Sarma's Avatar

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Joined: 30 Jul 2008
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6 Aug 2009 11:52:28 IST
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log 1000/256

= log 103 - log 2

=3 - 8 (0.301)

=0.592

Priyesh's Avatar

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6 Aug 2009 11:54:34 IST
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log(1000/256)= log1000 - log256 = log1000 - 8log2   (since 256 = 2^8 hence log256 = log2^8 = 8log2 (since loga^b = bloga))

= 3 - 8 * .301= 3 - 2.408 =  0.592


Blazing goIITian

Joined: 7 May 2007
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7 Aug 2009 10:07:29 IST
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log (1000/256).

on simplyfing we get,

 

edison's Avatar

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Joined: 19 Oct 2006
Posts: 7537
10 Aug 2009 13:43:52 IST
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Given log2= 0.301 evaluate log 1000/256

 

Sol) log 2 = 0.301

 

if here base is x then

 

x0.301 = 2

 

or x = 21/0.301

 

or x = 10

 

Thus base is 10

 

Now log 1000/256  = log 1000 - log 256 = log 103 - log 102.4082

 

= 3 - 2.4082 = 0.5918




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