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Algebra
given log2= 0.301 evaluate log 1000/256
log 1000/256
= log 103 - log 28
=3 - 8 (0.301)
=0.592
log(1000/256)= log1000 - log256 = log1000 - 8log2 (since 256 = 2^8 hence log256 = log2^8 = 8log2 (since loga^b = bloga))
= 3 - 8 * .301= 3 - 2.408 = 0.592
log (1000/256).
on simplyfing we get,
log 103 - log 28 = 3 - 8log2 = 3 - (8*0.301) = 3.000 - 2.408 = 0.592.
Given log2= 0.301 evaluate log 1000/256
Sol) log 2 = 0.301
if here base is x then
x0.301 = 2
or x = 21/0.301
or x = 10
Thus base is 10
Now log 1000/256 = log 1000 - log 256 = log 103 - log 102.4082
= 3 - 2.4082 = 0.5918
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log 1000/256
= log 103 - log 28
=3 - 8 (0.301)
=0.592