| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Mar 2008 12:29:16 IST
|
|
|
The three most recent appearences of halley's Comet were in the years 1835,1910 and 1986; the next occurence will be in 2061
Prove that
18351910+19862061 is divisible by 7 ??? No idea how they r related... plz help if u have ne clue might be out of JEE syllabus
|
" Always remember money isn't everything but make sure you have made a lot of it before talking such nonsense!"
- Bill Gates |
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Mar 2008 12:47:59 IST
|
|
|
might involve fermat's theorem... plz dont mind ppl if its not in JEE syllabus.. but i thought it was worth putting up!
|
" Always remember money isn't everything but make sure you have made a lot of it before talking such nonsense!"
- Bill Gates |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Mar 2008 14:11:33 IST
|
|
|
1835 = 7x262 + 1
1986= 7 x 284 - 2
Expand using binomial theorem , the remainder will be same as
1 1910 + ( -2 ) 2061
= 1 + ( -8 ) 687
= 1 + (- 7 -1) 687
= 1 - 1 = 0
so the remainder when divided by 7 is 0.
|
this reply: 40 points
(with 8 
in 8 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|