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Algebra

Blazing goIITian

Joined:	19 Feb 2007
Post:	1802

10 Mar 2007 19:00:12 IST

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Q) In how many ways 12 animals can be arranged, the animals contain horses,calves and cows(each greater in number than 12)

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ernst

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Joined: 17 Jan 2007

Posts: 19

10 Mar 2007 19:36:16 IST

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if each is greater than 12 4 permutation v have 2 select but in this case how can v select?v can take any no. so many cases r possible in short ur que. is missing something

Priyesh

Blazing goIITian

Joined: 18 Feb 2007

Posts: 1042

17 Mar 2007 13:04:12 IST

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Each position can be filled in 3 ways i.e horse,calve,or cow

total places are 12

therefore total no. of ways are 3*3*3.......12times = 3¹²

ANS IS 3¹²

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