IIT JEE , AIEEE Forum - Mathematics , Algebra - hey answer this questin and get a rate from me (if u get a correct ans)

harshthakar017

what is iⁱ

danny_007

e^-pi/2

harshthakar017

correct no more rates from now

sahilgupta_iit

harshthakar017

ok enough!!!
Now if you want a full rate post the solution!!!

RyuAmakusa

according to euler's formula eⁱ

=cos

+ i sin

and any complex no. z can be wrriten as z=r.eⁱ

where r is the modulus. so i can be wrriten as e^ipi/2 so

iⁱ = e^i.ipi/2 =e^-1pi/2(i.i=-1)

sahilgupta_iit

here's the solution:

bu euler's form;

e^i@ = cos@ + isin@

i = e^/2

iⁱ = e ^i/2*i

= e^-/2

aggmegha90

see i know a diff method . just take log of that and solve.

if z=x+iy

then, logz=logIzI + i*ampz

solving this way u get iⁱ is e^-pi/2

kindly rate me