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Algebra

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Blazing goIITian

Joined:	7 Feb 2007
Post:	1608

14 Feb 2009 17:56:30 IST

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How is {x} defined for NEGATIVE x

None

{x}=x-[x], x>0

What happens when x<0?

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Decoder

Blazing goIITian

Joined: 1 Apr 2007

Posts: 1084

14 Feb 2009 19:10:29 IST

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who told u this yaar...it is true for x<0 as well.....its a universal truth...

Tiger on prowl.......

Blazing goIITian

Joined: 27 Sep 2008

Posts: 545

15 Feb 2009 08:25:51 IST

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for x>0,{x} is written by dropping the integer part and stating onyl decimal part.

ex.for x=12.3213 {x}=0.3213

but we employ a different definition for x<0.....

consider x<0,first find {-x} ....here -x is positive..........

subtract {-x} from 1.

proof::x=p+q where p is the integer part and q is decimal part(with negative signs)

x=(p-1)+(1+q)

this is done to maintain consistency ie 0<={x}<1

hence {x}=(1+q) ie 1+{-x}

Tiger on prowl.......

Blazing goIITian

Joined: 27 Sep 2008

Posts: 545

15 Feb 2009 08:27:11 IST

Like 0 people liked this

ex.x=-12.312-x=12.312;{x}=0.312thus {x}=1-0.312=0.688

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