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Algebra
How to find largest among 2^24 and 3^12...or exactly between a^b and c^d(esp if b and d are very large) and if their value is too close
12 log(3) = 5.72545506
"Compare logs. :)"
mayb u can put 12th root of both the no.s. now compare 2^2 and 3. so 2^24>3^12.
it works on the fact that if a>b then a^y>b^y
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12 log(3) = 5.72545506
24 log(2) = 7.2247199
"Compare logs. :)"