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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2008 16:33:32 IST
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hot find the values of log without using a log book for ex - log 3 , log 3/4 , log 4/5, log 22/33
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2008 16:59:55 IST
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i wanted to know that tooo..
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Here I am this is ME!!...and there's no where else on earth I'd rather be!!!!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2008 17:01:59 IST
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jjust rememnber....log3 base 10 is 0.47 and log2 base 10 is 0.3 and log5 base 10 is 0.7...well log3/4 is log3-log4 and all tht log prop...and also log2 base e is 0.693 as we know tht loga base e =2.303loga base 10 hope u got it...rate if usefull....
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The only place where you will find success before hard work is in the dictionary
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learn the values for log2,log3 rest can be derived.
log2 = 0.3010 log3 = 0.4771
log(3/4) = log3 - log4 = log3 - 2log2
log(4/5) = 2log2 - log5 ..now log5 would be somewhere around the "mean" of log 4 and log6..and log4 = 2log2 and log6 = log2 + log3..
log(22/23) = log22 - log23.. = log2 + log11 - log23..
log11 would be close to the "mean" of log 10 and log12 and log 23 would be the mean of log 22 and log24..
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There is no better feeling in this world than being a winner! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2008 17:03:23 IST
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@ joyfrancis ,....perfect....
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2008 17:04:21 IST
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actually those log 2 ..3 ..5 are imp for chemistry....ionic equilib ...and all those chapters...
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2008 17:07:06 IST
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@ganesha jawab...millgaya!!!???
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Here I am this is ME!!...and there's no where else on earth I'd rather be!!!!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2008 17:16:46 IST
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ok what if the numbers r large and r prime numbers
something like log 43/23
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2008 17:19:28 IST
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learn these three log2(=0.3010 log3(0.4771 log7(0.8450 rest comes easily 4=2~2==>log 4=2log 2=.6020 5=10/2==>log5=1-log2= .6989 6=2*3 etc now for higher numbers and fraction(like 22/33 which is=2/3) write down in decimal form up to two places or better in form of a+p/q iff a>>p/q ignore p/q let us take an example: {example pending }{will post soon} eg 102/101 =1.009 etc than use praportianal approximation
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My name is Arnav.
Hoping we'll meet in IIT next year ! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2008 17:55:35 IST
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oh!!! u want abt log43/23 ???well now u ll have to use a log book.....i dont think any ques paper will ask such type of values....they wont test our knowledge and memory from log tables...rite?????
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The only place where you will find success before hard work is in the dictionary
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2008 17:56:40 IST
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may be u can do it tht way log43/23 as log40/20 which is log2 ....but tht wont give xaxct value... //cheers//
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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