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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Apr 2008 08:36:15 IST
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how to find the no. of real roots of this equation
root(x+1)-root(x-1)=root(4x-1)
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"Only two things are infinite, the universe and human stupidity, and I'm not sure about the former." --Albert Einstein |
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the square both the sides once
then simplify the expression and then again square it
u ll get a quadratic then solve it
to check ur solution just put the values u calculated in the given expression and check if those values are satisfied................i mean if for some value if u get something -ve in the square root then that solution can be discarded
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4 Apr 2008 11:01:54 IST
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dream is right.
in general , whenever u square an equation , u should substitute the values and check if it satisfies the equation. u need to check whether it is completely correct . even if all the terms inside the square root are positive, the answer might be still wrong.
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4 Apr 2008 11:13:10 IST
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there should be no real roots
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