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Forum Index -> Algebra like the article? email it to a friend.  
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saurabh16_singh (0)

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<Q:>Three brothers whose ages are in G.P. divide a 
certain sum of money among themselves in proportin
 to their ages .If they do that 3 yrs. later when 
the youngest brother is half the oldest he will recive 
Rs.105(youngest) and the middle brother gets Rs.15 more
 than he gets now.Give the ages of the brothers.
    
Asmita (475)

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Please make it clear to me whether after 3 yrs. the ages of the 3 brothers are in G.P. or not.
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saurabh16_singh (0)

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no the ages r not in gp after 3 yrs
 
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krishna.gopal (2149)

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Let there ages by a, ar, ar^2 (Ascending order)
Let the money to be divided is x Rs
The three equations given in the problem are
(a+3)/(ar^2+3)=(1/2)                                        ------(i)
x*(a+3)/(a+ar+ar^2+9)=105                              ------(ii)
x*(ar+3)/(a+ar+ar^2+9)-x*ar/(a+ar+ar^2)=15     ------(iii)
 
Try solving these set of equation. I have tried a bit but i am unable to solve till now. Do you have answer of this problem

Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi
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devesh_l2k007 (107)

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nice job krishna
but the answers r
12,18,27
a=12; r=3/2
and total money = 462
HOWZZAT

devesh

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devesh_l2k007 (107)

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RATE PLS

devesh

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