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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Sep 2007 19:48:54 IST
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solve for x,y in +ve integral values for the equation x^2-61y^2=1
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14 Sep 2007 19:59:44 IST
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there is no solution
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14 Sep 2007 23:21:21 IST
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If no one can solve this ,then i'm "Mr. no one".
x=1766319049,y=226153980
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15 Sep 2007 12:55:18 IST
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hello mr.noone can u plz give the procedure
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15 Sep 2007 12:58:59 IST
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the values does n't satisfy the eq i checked in cal
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15 Sep 2007 13:13:28 IST
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x^2 = 3119882982860264401
y^2 = 51145622669840400
61y^2= 3119882982860264400
Let me know which calculator you used to calculate 19 digit nos.
This equation is of the form x^2-dy^2=1
This equation is known as pell's equation and can be solved by performing the continued fraction expansion of d. It is surely beyond the scope of JEE.
For more information visit http://en.wikipedia.org/wiki/Pell's_equation
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15 Sep 2007 14:22:01 IST
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i used the sientific cal in system but the mis which i've done is i didn't square y thats the fault yar can u plz explain hw to solve pels equation that eq tok the mathematetians to workout for an year
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