
|
| physics chemistry maths science forums |
|
|
|
| |
|
|

| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Dec 2007 16:49:38 IST
|
|
|
How many integers between 100 and 150, inclusive, cannot be evenly divided by 3 nor 5?
regards rachu
|
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Dec 2007 20:30:46 IST
|
|
|
The numbers are 105, 120 and 135. Rate me if i'm right.
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Dec 2007 08:26:08 IST
|
|
|
The number is integers between 100 and 150, which are evenly divisible by 3 is 17 (102,105,108,.....150) The number is integers between 100 and 150, which are evenly divisible by 5 is 11 (100,105,110,....150) The number is integers between 100 and 150, which are evenly divisible by both 3 and 5 is 4 (105,120,135,150) Let A be the set of integers between 100 and 150, which not evenly divisible by 3. Let A be the set of integers between 100 and 150, which not evenly divisible by 5. So, we have, n(A)=17, n(B)=11, n(AnB)=4. Therefore, n(AuB)=17+11-4=24. Here we are asked to find the no of integers which are neither divisible by 3 nor 5. ie, we need to find n(A'nB'), where A' represents complimentary set of A. By De'Morgans law, n(A'nB') = n((AuB)')=51-n(AuB)=51-24 = 27. So, the answer is 27.
|
Satyaram B V,
General Secretary, Mandakini Hostel,
IIT Madras |
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Dec 2007 08:27:36 IST
|
|
|
Visit http://en.wikipedia.org/wiki/De_Morgan's_laws for details on Demorgans laws
|
Satyaram B V,
General Secretary, Mandakini Hostel,
IIT Madras |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|