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5 Sep 2010 19:25:26 IST

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IF 5 BISCUITS R DISTRIBUTED AMONG 3 BEGGARS, WHAT IS THE PROBABILITY THAT A PARTICULAR BEGGAR GETS 2

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IF 5 BISCUITS R DISTRIBUTED AMONG 3 BEGGARS, WHAT IS THE PROBABILITY THAT A PARTICULAR BEGGAR GETS 2 BISCUITS. THE ANSWER FOR THIS QUESTION IS 80/243 PLEASE HELP ME 2 SOLVE THE QUESTION

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Krishna Gopal Singh

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Joined: 29 Dec 2006

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7 Sep 2010 23:12:22 IST

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Number of ways to decide which biscuits out of five is to be given to that begger is 5C2. The remaning three biscuits must be distributed among two beggers. So total number of ways to distribute biscuits = 5C2*2*2*2 = 80 Number of ways to distribute biscuits = 3^5 = 243 So required probability = 80/243

karthik

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10 Sep 2010 17:38:54 IST

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5C2*2*2*2 ???????

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