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Algebra

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27 Dec 2007 17:56:23 IST

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If 6 / 3^x = 2^x . 3^y then x + y = ?

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If 6 / 3^x = 2^x . 3^y then x + y = ?

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Anshuman Bhujabal

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Joined: 18 Aug 2007

Posts: 123

28 Dec 2007 06:43:58 IST

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I think the answer is 1

6 = 2^x.3^x+y

2.3 = 2^x.3^x+y

Comparing we get, x+y=1

I hopw my answer is correct....

If yes then plz rate ....

Dinesh Babu

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Joined: 18 Dec 2006

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28 Dec 2007 09:23:12 IST

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continuing further we get
1 = 2^(x-1).3^(x+y-1)
implies x must be 1
and y=0
so we get x+y=1......!

Bhaskar Tetarbe

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Joined: 15 Jul 2007

Posts: 245

28 Dec 2007 09:48:45 IST

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6 / 3^x = 2^x . 3^y
or 6 = (3.2)^x.3^y
or 6 = 6^x.3^y
Comparing the 2 sides only values, x = 1, y = 0 can satisfy this.
Therefore, x+ y = 1

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