32^(32^32)
let(32^32) be y
so32^(32^32)/7 =32^y/7=(32*32*32*------------y times)/7
32^y/7 = [(28+4)*{32*32*-------------------------(y-1) times}]/7
32^y/7 = [28{32*32*----------------------(y-1)times}/7]+[4(32*32*----------------------(y-1)times)}/7
32^y/7 = [4*32^(y-1)]+[4*32^(y-1)]/7
32^y = 7*[4*32^(y-1)] + [4*32^(y-1)]
as you can see that above expression has taken form
dividend = divisor * quotient +remainder
so,remainder = 4*32^(y-1) ,where y=32^32
32^(32^32)
let(32^32) be y
so32^(32^32)/7 =32^y/7=(32*32*32*------------y times)/7
32^y/7 = [(28+4)*{32*32*-------------------------(y-1) times}]/7
32^y/7 = [28{32*32*----------------------(y-1)times}/7]+[4(32*32*----------------------(y-1)times)}/7
32^y/7 = [4*32^(y-1)]+[4*32^(y-1)]/7
32^y = 7*[4*32^(y-1)] + [4*32^(y-1)]
as you can see that above expression has taken form
dividend = divisor * quotient +remainder
so,remainder = 4*32^(y-1) ,where y=32^32