|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Dec 2007 17:58:28 IST
|
|
|
if a + b + c = 0 then a(b-c)^2 + b(c-a)^2 + c(a-b)^2 / abc = ??
|
|
|
|
27 Dec 2007 18:25:30 IST
|
|
|
a[b-c]2 + b[c-a]2 +c[a-b]2 /abc = a{[b+c]2-4bc} + b{[c+a]2-4ca} + c{[a+b]2-4ab}/abc
=a{a2-4bc} + b{b2-4ca} + c{c2-4ab}/abc
=a3+b3+c3-12abc/abc
=3abc-12abc/abc [ since if a+b+c=0,a3+b3+c3=3abc]
=-9abc/abc
=- 9
|
"Nenenthedhavano naake teleedu"
|
this reply: 7 points
(with 1 
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
29 Dec 2007 13:51:43 IST
|
|
|
={a{b^2+c^2-2bc] +b[c^2+a^2-2ac]+c[a^2+b^2-2ab] } /abc
=ab[a+b] +ac[a+c] +bc[b+c]/abc -[6]
=-3-6=-9
simpl yaar rate me
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
